We would like to inform our users that the board administrator contact page has been temporarily disabled . Unfortunately, we have been receiving an overwhelming amount of spam messages through that channel, which has made it difficult to manage legitimate inquiries effectively.
We understand that ...
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- Thu May 29, 2025 7:39 am
- Forum: Meta
- Topic: Important Notice: Administrator Contact Page Disabled
- Replies: 0
- Views: 1710
- Thu May 29, 2025 7:00 am
- Forum: Meta
- Topic: Forum migration
- Replies: 0
- Views: 10148
Forum migration
Dear Members and Guests of mathimatikoi.org,
we would like to inform you that mathimatikoi.org has recently undergone a server migration in order to improve performance, stability, and scalability for the long term. As part of this upgrade, we also had to update and propagate our DNS (Domain Name ...
we would like to inform you that mathimatikoi.org has recently undergone a server migration in order to improve performance, stability, and scalability for the long term. As part of this upgrade, we also had to update and propagate our DNS (Domain Name ...
- Sun Apr 13, 2025 11:31 am
- Forum: Meta
- Topic: Forum upgrade to latest version
- Replies: 4
- Views: 30049
Re: Forum upgrade to latest version
Greetings everyone,
we are pleased to announce that the forum software has been upgraded to the latest version hardening the security of our website and resolving some issues noticed in previous releases.
All language packs will be updated within the next hours.
Thank you.
we are pleased to announce that the forum software has been upgraded to the latest version hardening the security of our website and resolving some issues noticed in previous releases.
All language packs will be updated within the next hours.
Thank you.
- Wed Dec 04, 2024 6:04 pm
- Forum: Meta
- Topic: Forum upgrade to latest version
- Replies: 4
- Views: 30049
Re: Forum upgrade to latest version
Greetings everyone,
we are pleased to announce that the forum software has been upgraded to the latest version hardening the security of our website and resolving some issues noticed in previous releases.
All language packs will be updated within the next hours.
Thank you.
we are pleased to announce that the forum software has been upgraded to the latest version hardening the security of our website and resolving some issues noticed in previous releases.
All language packs will be updated within the next hours.
Thank you.
- Thu Oct 31, 2024 8:27 am
- Forum: Meta
- Topic: Forum upgrade to latest version
- Replies: 4
- Views: 30049
Re: Forum upgrade to latest version
Greetings everyone,
we wanted to inform you that, unfortunately, the previous server hosting our forum unexpectedly went offline and ceased all operations without any prior notice. This sudden shutdown means that some of our recent data and posts may have been lost in the process.
The good news is ...
we wanted to inform you that, unfortunately, the previous server hosting our forum unexpectedly went offline and ceased all operations without any prior notice. This sudden shutdown means that some of our recent data and posts may have been lost in the process.
The good news is ...
A series
Evaluate the series
$$\mathcal{S} = \sum_{n=1}^{\infty} (-1)^{n-1} \ln \frac{n+1}{n}$$
$$\mathcal{S} = \sum_{n=1}^{\infty} (-1)^{n-1} \ln \frac{n+1}{n}$$
- Wed Apr 12, 2023 10:01 pm
- Forum: Analytic Geometry
- Topic: Vector algebra
- Replies: 0
- Views: 5621
Vector algebra
Let $\mathbf{a} , \mathbf{b}, \mathbf{c}$ be three non coplanar vector. If $\displaystyle{\mathbf{a}' = \frac{\mathbf{b} \times \mathbf{c}}{\left [ \mathbf{a,b, c} \right ]} \; , \; \mathbf{b}' = \frac{\mathbf{c} \times \mathbf{a}}{\left [ \mathbf{a,b, c} \right ]} \; , \; \mathbf{c}' = \frac ...
- Sun Mar 12, 2023 4:03 pm
- Forum: Calculus
- Topic: An infinite product
- Replies: 0
- Views: 4879
An infinite product
Let $\mathcal{F}_n$ denote the $n$ -th Fibonacci number and $\mathcal{L}_n$ the $n$ – th Lucas. Prove that
$$\prod_{n=1}^{\infty} \left ( 1 + \frac{1}{\mathcal{F}_{2^n +1} \mathcal{L}_{2^n+1}} \right ) = \frac{3}{\varphi^2}$$
$$\prod_{n=1}^{\infty} \left ( 1 + \frac{1}{\mathcal{F}_{2^n +1} \mathcal{L}_{2^n+1}} \right ) = \frac{3}{\varphi^2}$$
- Sun Mar 12, 2023 3:52 pm
- Forum: Meta
- Topic: Forum upgrade to latest version
- Replies: 4
- Views: 30049
Re: Forum upgrade to latest version
Greetings everyone,
we are pleased to announce that the forum software has been upgraded to the latest version hardening the security of our website. You will notice that many cosmetic things have been restored to normal. This new version is compatible with php 8.2 that our server is currently ...
we are pleased to announce that the forum software has been upgraded to the latest version hardening the security of our website. You will notice that many cosmetic things have been restored to normal. This new version is compatible with php 8.2 that our server is currently ...
- Wed Nov 16, 2022 8:30 am
- Forum: Meta
- Topic: Forum upgrade to latest version
- Replies: 4
- Views: 30049
Forum upgrade to latest version
Greetings,
we have updated the forum to its latest version phpbb 3.3.x. You will find that many bugs have been fixed in this latest version. We would like to also inform you that the ability to add tags has been restored and now it's working flawlessly. You can select among many different tags to ...
we have updated the forum to its latest version phpbb 3.3.x. You will find that many bugs have been fixed in this latest version. We would like to also inform you that the ability to add tags has been restored and now it's working flawlessly. You can select among many different tags to ...
