Tough integral

Calculus (Integrals, Series)
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Aryan
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Joined: Sat Mar 16, 2024 11:46 am

Tough integral

#1

Post by Aryan »

$$I=\int_{\arccos(1/4)}^{\pi/2}\arccos\left(\cos x\left(2\sin^2x+\sqrt{1+4\sin^4x}\right)\right)\mathrm dx=\frac{\pi^2}{40}$$

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