is contractive?
- Grigorios Kostakos
- Founder
- Posts: 461
- Joined: Mon Nov 09, 2015 1:36 am
- Location: Ioannina, Greece
is contractive?
A sequence \(\{{\alpha_{n}}\}_{n=1}^{\infty}\) is contractive iff there exists a constant \(c\), with \(0<c<1\), such that, for all \(n\in\mathbb{N}\), holds:
\[|a_{n+2}-a_{n+1}|\leqslant c\,|a_{n+1}-a_{n}|\]
Examine if the sequence
\[a_{n}=({\underbrace{\sin\circ\sin\circ\ldots\circ\sin}_{n-{\rm{times}}}})({n})\,,\;n\in\mathbb{N}\,,\]
is contractive.
\[|a_{n+2}-a_{n+1}|\leqslant c\,|a_{n+1}-a_{n}|\]
Examine if the sequence
\[a_{n}=({\underbrace{\sin\circ\sin\circ\ldots\circ\sin}_{n-{\rm{times}}}})({n})\,,\;n\in\mathbb{N}\,,\]
is contractive.
Grigorios Kostakos
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