On measure theory
Posted: Mon Dec 07, 2015 1:39 pm
Let \(\displaystyle{f\,,g:\mathbb{R}\longrightarrow \mathbb{R}}\) be two continuous functions such that
\(\displaystyle{f=g}\) \(\displaystyle{\,\,\,\,\,\,\,\,\lambda}\) a.e (almost everywhere),
where \(\displaystyle{\lambda}\) stands for \(\displaystyle{\rm{Lebesque}}\) measure.
Prove that \(\displaystyle{f=g}\) .
\(\displaystyle{f=g}\) \(\displaystyle{\,\,\,\,\,\,\,\,\lambda}\) a.e (almost everywhere),
where \(\displaystyle{\lambda}\) stands for \(\displaystyle{\rm{Lebesque}}\) measure.
Prove that \(\displaystyle{f=g}\) .