\( \int_{0}^{\infty}{e^{-x}\ln\bigl({\ln\bigl({e^x+\sqrt{e^{2x}-1}\,}\bigr)}\bigr) \;dx}\)
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\( \int_{0}^{\infty}{e^{-x}\ln\bigl({\ln\bigl({e^x+\sqrt{e^{2x}-1}\,}\bigr)}\bigr) \;dx}\)
Evaluate the following integral :
$$ \displaystyle\int_{0}^{\infty}{e^{-x}\ln\bigl({\ln\bigl({e^x+\sqrt{e^{2x}-1}\,}\bigr)}\bigr) \;{\rm d}x}$$
$$ \displaystyle\int_{0}^{\infty}{e^{-x}\ln\bigl({\ln\bigl({e^x+\sqrt{e^{2x}-1}\,}\bigr)}\bigr) \;{\rm d}x}$$
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Re: \( \int_{0}^{\infty}{e^{-x}\ln\bigl({\ln\bigl({e^x+\sqrt{e^{2x}-1}\,}\bigr)}\bigr) \;dx}\)
Here http://mathimatikoi.org/forum/viewtopic ... 2161#p2161" onclick="window.open(this.href);return false;Tolaso J Kos wrote:Evaluate the following integral :
$$ \displaystyle\int_{0}^{\infty}{e^{-x}\ln\bigl({\ln\bigl({e^x+\sqrt{e^{2x}-1}\,}\bigr)}\bigr) \;{\rm d}x}$$
Regards
Civil Engineer
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