On covarient derivative

Differential Geometry
Post Reply
Tsakanikas Nickos
Community Team
Posts: 314
Joined: Tue Nov 10, 2015 8:25 pm

On covarient derivative

#1

Post by Tsakanikas Nickos »

Bearing in mind this exercise , prove the following assertion :

Let \( \displaystyle V \) and \( \displaystyle W \) be two differential vector fields along the parametrized curve \( \displaystyle \alpha : I \longrightarrow S \) such that \( \displaystyle \Big| V(t) \Big| = \Big| W(t) \Big| = 1 , \, \forall t \in I \), where \( \displaystyle I \subset \mathbb{R} \) is an interval and \( \displaystyle S \) is a regular surface. Then \[ \displaystyle \Big[ \frac{DW}{dt} \Big] - \Big[ \frac{DV}{dt} \Big] = \frac{d \phi}{dt} \]where \( \displaystyle \phi \) is one of the differentiable determinations of the angle from \( \displaystyle V \) to \( \displaystyle W \).
Post Reply

Create an account or sign in to join the discussion

You need to be a member in order to post a reply

Create an account

Not a member? register to join our community
Members can start their own topics & subscribe to topics
It’s free and only takes a minute

Register

Sign in

Who is online

Users browsing this forum: No registered users and 5 guests