Definition 2: A covariant $k$-tensor is called symmetric if its value is unchanged by interchanging any pair of its arguments:
\[ T(X_{1}, \dots, X_{i}, \dots, X_{j}, \dots, X_{k}) = T(X_{1}, \dots, X_{j}, \dots, X_{i}, \dots, X_{k}) \]whenever $ 1 \leq i < j \leq k $.
Show that the following are equivalent for a covariant $k$-tensor $T$:
- $T$ is symmetric.
- For any vectors $X_{1}, \dots, X_{k}$ the value of $T(X_{1}, \dots, X_{k})$ is unchanged when $ X_{1}, \dots, X_{k} $ are rearranged in any order.
- The components $T_{i_{1} \dots i_{k}} = T(E_{i_{1}}, \dots, E_{i_{k}})$ of $T$ with respect to any basis $ \left\{ E_{i} \right\} $ of $V$ are unchanged by any permutation of the indices.