Basic Ring Theory - 13
-
- Community Team
- Posts: 314
- Joined: Tue Nov 10, 2015 8:25 pm
Basic Ring Theory - 13
Let \( A \) be an integrally closed, notherian integral domain. Show that
\[ \displaystyle A \ = \bigcap_{ \mathfrak{p} \ : \ ht(\mathfrak{p}) \ =1 } A_{\mathfrak{p}} \]
where the intersection is taken over all prime ideals \( \mathfrak{p} \subset A \) with height \( ht(\mathfrak{p})=1 \).
\[ \displaystyle A \ = \bigcap_{ \mathfrak{p} \ : \ ht(\mathfrak{p}) \ =1 } A_{\mathfrak{p}} \]
where the intersection is taken over all prime ideals \( \mathfrak{p} \subset A \) with height \( ht(\mathfrak{p})=1 \).
Create an account or sign in to join the discussion
You need to be a member in order to post a reply
Create an account
Not a member? register to join our community
Members can start their own topics & subscribe to topics
It’s free and only takes a minute
Sign in
Who is online
Users browsing this forum: No registered users and 8 guests