Page 1 of 1

Irrational number

Posted: Tue Nov 10, 2015 4:02 pm
by Tolaso J Kos
Let $N \in \mathbb{N} \mid N>1$. Prove that the number:

$$\mathcal{N}= \sqrt{1\cdot 2 \cdot 3 \cdot 4 \cdots (N-1)\cdot N}$$

is irrational.
Hidden message
May we have an alternate proof without Bertrand's postulate,or is this impossible?

Re: Irrational number

Posted: Wed Aug 01, 2018 9:33 am
by Riemann
Let $p \leq N$ be the last prime. If we prove that between $p$ and $N$ does not exist a number that has $p$ as a factor we are done. So, we need to prove that $2p>N$. But this is exactly what Bertrand's postulate says.