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A well known equality

Posted: Tue Jan 19, 2016 3:42 pm
by Tolaso J Kos
We use the notations used in the previous two posts (namely here and here).

Prove that:

$$[a, (b, c)]=([a, b], [b, c])$$

Although this equality is in fact too known, pardon me, but I don't have a solution.