\(\alpha_{n}=2\,\alpha_{n-1}+2^{-2(n-1)}\)

Real Analysis
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Grigorios Kostakos
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\(\alpha_{n}=2\,\alpha_{n-1}+2^{-2(n-1)}\)

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Post by Grigorios Kostakos »

For the sequence $\left({\alpha_{n}}\right)_{n\in\mathbb{N}\cup\{0\}}$ of real numbers defined recursively as
\[\alpha_{n}=2\,\alpha_{n-1}+2^{-2(n-1)}\,,\; n\in\mathbb{N}\,,\quad \alpha_0=1\,:\]
  1. Find the general form of \(\alpha_{n}\).
  2. Find the values of real number $\beta$ for which the \(\displaystyle\mathop{\lim}\limits_{n\rightarrow{+\infty}}\frac{2^{\alpha_{n}}}{2^{{\beta}^{n}}}\) is a real number.
Grigorios Kostakos
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