\mathop{(\underbrace{h\circ{h}\circ\ldots\circ{h}})}\limits_{n\;{\text{times}}}(x)\,,&{n}\in\mathbb{Z}^{+}\\
x\,,&{n}=0\\
\mathop{(\underbrace{{h^{-1}\circ{h^{-1}}\circ\ldots\circ{h^{-1}}}})}\limits_{n\;{\text{times}}}(x)\,,&{n}\in\mathbb{Z}^{-}
\end{array}}\right.\,,$$ where $h^{-1}$ is the inverse function of $h$.
If
- for every $x\in\mathbb{R}$, there exists an non-negative number $c_x$, such that, for every ${n}\in\mathbb{Z}$, holds
$$\left|{h^{[\rm{n+1}]}(x)-h^{[n]}(x)}\right|=c_x$$ and - there exists $x_0\in\mathbb{R}$, such that $h(x_0)=x_0$,