Let \(\displaystyle{\left(G,\cdot\right)}\) be a group and \(\displaystyle{f:G\longrightarrow G}\)
be a homomorphism which is onto \(\displaystyle{G}\) .
If \(\displaystyle{H\leq G}\) such that \(\displaystyle{[G:H]=n\in\mathbb{N}}\), then prove that
\(\displaystyle{[G:f^{-1}(H)]=n}\) .
Search found 375 matches
- Wed Nov 18, 2015 5:10 pm
- Forum: Algebraic Structures
- Topic: On group theory 8 (An easy one)
- Replies: 1
- Views: 2099
- Wed Nov 18, 2015 5:07 pm
- Forum: Algebraic Structures
- Topic: On group theory 7
- Replies: 3
- Views: 3396
On group theory 7
Let \(\displaystyle{\left(G,+\right)}\) be an abelian group.
Find the cardinality of \(\displaystyle{\rm{Hom}(\mathbb{Z},G)}\).
Find the cardinality of \(\displaystyle{\rm{Hom}(\mathbb{Z},G)}\).
- Wed Nov 18, 2015 5:03 pm
- Forum: Algebraic Structures
- Topic: On group theory 2
- Replies: 2
- Views: 3052
Re: On group theory 2
Thank you mr. Demetres.
- Wed Nov 18, 2015 5:02 pm
- Forum: Complex Analysis
- Topic: Are These Sets Biholomorphic?
- Replies: 2
- Views: 3190
Re: Are These Sets Biholomorphic?
1.Answer The unit disc \(\displaystyle{D=\left\{z\in\mathbb{C}: \left|z\right|<1\right\}}\) is not biholomorphic to \(\displaystyle{\mathbb{C}}\) . Indeed, suppose that the unit disc \(\displaystyle{D}\) is biholomorphic to \(\displaystyle{\mathbb{C}}\) . Then, there exists a holomorphic function \...
- Sun Nov 15, 2015 7:52 pm
- Forum: Analysis
- Topic: Where is $f$ continuous?
- Replies: 1
- Views: 2672
Re: Where is $f$ continuous?
For each \(\displaystyle{x\in\mathbb{R}}\) holds : \(\displaystyle{\dfrac{x^{2\,n}-1}{x^{2\,n}+1}=\dfrac{\left(x^2\right)^{n}-1}{\left(x^2\right)^{n}+1}}\) . Let \(\displaystyle{x\in\mathbb{R}}\) . If \(\displaystyle{x\in\left(-\infty,-1\right)\cup\left(1,+\infty\right)}\) , then \(\displaystyle{x^2...
- Sun Nov 15, 2015 7:06 pm
- Forum: Calculus
- Topic: Some indefinite integrals
- Replies: 6
- Views: 4608
Re: Some indefinite integrals
Solution for ii) Apostolos, we have \(\displaystyle{2+\sin\,(2\,x)}\). The integration interval is \(\displaystyle{I=\mathbb{R}}\) . \(\displaystyle{2+\sin\,(2\,x)=1+\left(\sin\,x+\cos\,x\right)^2=1+2\,\sin^2\,\left(x+\frac{\pi}{4}\right)\,,x\in\mathbb{R}}\) , so \(\displaystyle{\int \dfrac{\sin\,x}...
- Fri Nov 13, 2015 5:53 pm
- Forum: Functional Analysis
- Topic: Integral operator
- Replies: 1
- Views: 2759
Integral operator
Consider the real normed space \(\displaystyle{\left(C\,(\left[0,1\right]),||\cdot||_{\infty}\right)}\) and the map \(\displaystyle{T:C\,(\left[0,1\right])\longrightarrow C\,(\left[0,1\right])\,,f\mapsto T(f):\left[0,1\right]\longrightarrow \mathbb{R}\,,T(f)(t)=\int_{0}^{t}f(s)\,\mathrm{d}s}\) . A. ...
- Fri Nov 13, 2015 12:22 pm
- Forum: General Topology
- Topic: Compact Polish Space
- Replies: 1
- Views: 2578
Re: Compact Polish Space
We define \(\displaystyle{\arctan\,(+\infty)=\dfrac{\pi}{2}}\) . 1. The function \(\displaystyle{\rho}\) is a metric function on \(\displaystyle{X}\) : Obviously, \(\displaystyle{\rho(x,y)\in\mathbb{R}\cap \left[0,+\infty\right)}\) and \(\displaystyle{\rho(x,y)=0\iff x=y}\) . Also, \(\displaystyle{\...
- Fri Nov 13, 2015 10:46 am
- Forum: Calculus
- Topic: 2 variable Integration
- Replies: 1
- Views: 2036
Re: 2 variable Integration
Hi jacks. Since the function \(\displaystyle{f}\) is continuous ( i suppose that you mean at \(\displaystyle{\mathbb{R}}\)) , we have that : \(\displaystyle{\begin{aligned} F(x)&=\int_{0}^{x}\left((2\,t+3)\,\int_{1}^{2}f(u)\,\mathrm{d}u\right)\,\mathrm{d}t\\&=\int_{1}^{2}f(u)\,\mathrm{d}u\,\...
- Thu Nov 12, 2015 2:20 pm
- Forum: Functional Analysis
- Topic: Fixed point
- Replies: 5
- Views: 4544
Fixed point
Let \(\displaystyle{\left(X,||\cdot||\right)}\) be a real \(\displaystyle{\rm{Banach}}\) space and \(\displaystyle{T\in\mathbb{B}(X,X)}\) such that \(\displaystyle{\sum_{n=0}^{\infty}||T^{n}||<\infty}\) . If \(\displaystyle{y\in X}\), then we define \(\displaystyle{S_{y}:X\longrightarrow X}\) by \(\...