Search found 375 matches

by Papapetros Vaggelis
Wed Nov 18, 2015 5:10 pm
Forum: Algebraic Structures
Topic: On group theory 8 (An easy one)
Replies: 1
Views: 2099

On group theory 8 (An easy one)

Let \(\displaystyle{\left(G,\cdot\right)}\) be a group and \(\displaystyle{f:G\longrightarrow G}\)

be a homomorphism which is onto \(\displaystyle{G}\) .

If \(\displaystyle{H\leq G}\) such that \(\displaystyle{[G:H]=n\in\mathbb{N}}\), then prove that

\(\displaystyle{[G:f^{-1}(H)]=n}\) .
by Papapetros Vaggelis
Wed Nov 18, 2015 5:07 pm
Forum: Algebraic Structures
Topic: On group theory 7
Replies: 3
Views: 3396

On group theory 7

Let \(\displaystyle{\left(G,+\right)}\) be an abelian group.

Find the cardinality of \(\displaystyle{\rm{Hom}(\mathbb{Z},G)}\).
by Papapetros Vaggelis
Wed Nov 18, 2015 5:03 pm
Forum: Algebraic Structures
Topic: On group theory 2
Replies: 2
Views: 3052

Re: On group theory 2

Thank you mr. Demetres.
by Papapetros Vaggelis
Wed Nov 18, 2015 5:02 pm
Forum: Complex Analysis
Topic: Are These Sets Biholomorphic?
Replies: 2
Views: 3190

Re: Are These Sets Biholomorphic?

1.Answer The unit disc \(\displaystyle{D=\left\{z\in\mathbb{C}: \left|z\right|<1\right\}}\) is not biholomorphic to \(\displaystyle{\mathbb{C}}\) . Indeed, suppose that the unit disc \(\displaystyle{D}\) is biholomorphic to \(\displaystyle{\mathbb{C}}\) . Then, there exists a holomorphic function \...
by Papapetros Vaggelis
Sun Nov 15, 2015 7:52 pm
Forum: Analysis
Topic: Where is $f$ continuous?
Replies: 1
Views: 2672

Re: Where is $f$ continuous?

For each \(\displaystyle{x\in\mathbb{R}}\) holds : \(\displaystyle{\dfrac{x^{2\,n}-1}{x^{2\,n}+1}=\dfrac{\left(x^2\right)^{n}-1}{\left(x^2\right)^{n}+1}}\) . Let \(\displaystyle{x\in\mathbb{R}}\) . If \(\displaystyle{x\in\left(-\infty,-1\right)\cup\left(1,+\infty\right)}\) , then \(\displaystyle{x^2...
by Papapetros Vaggelis
Sun Nov 15, 2015 7:06 pm
Forum: Calculus
Topic: Some indefinite integrals
Replies: 6
Views: 4608

Re: Some indefinite integrals

Solution for ii) Apostolos, we have \(\displaystyle{2+\sin\,(2\,x)}\). The integration interval is \(\displaystyle{I=\mathbb{R}}\) . \(\displaystyle{2+\sin\,(2\,x)=1+\left(\sin\,x+\cos\,x\right)^2=1+2\,\sin^2\,\left(x+\frac{\pi}{4}\right)\,,x\in\mathbb{R}}\) , so \(\displaystyle{\int \dfrac{\sin\,x}...
by Papapetros Vaggelis
Fri Nov 13, 2015 5:53 pm
Forum: Functional Analysis
Topic: Integral operator
Replies: 1
Views: 2759

Integral operator

Consider the real normed space \(\displaystyle{\left(C\,(\left[0,1\right]),||\cdot||_{\infty}\right)}\) and the map \(\displaystyle{T:C\,(\left[0,1\right])\longrightarrow C\,(\left[0,1\right])\,,f\mapsto T(f):\left[0,1\right]\longrightarrow \mathbb{R}\,,T(f)(t)=\int_{0}^{t}f(s)\,\mathrm{d}s}\) . A. ...
by Papapetros Vaggelis
Fri Nov 13, 2015 12:22 pm
Forum: General Topology
Topic: Compact Polish Space
Replies: 1
Views: 2578

Re: Compact Polish Space

We define \(\displaystyle{\arctan\,(+\infty)=\dfrac{\pi}{2}}\) . 1. The function \(\displaystyle{\rho}\) is a metric function on \(\displaystyle{X}\) : Obviously, \(\displaystyle{\rho(x,y)\in\mathbb{R}\cap \left[0,+\infty\right)}\) and \(\displaystyle{\rho(x,y)=0\iff x=y}\) . Also, \(\displaystyle{\...
by Papapetros Vaggelis
Fri Nov 13, 2015 10:46 am
Forum: Calculus
Topic: 2 variable Integration
Replies: 1
Views: 2036

Re: 2 variable Integration

Hi jacks. Since the function \(\displaystyle{f}\) is continuous ( i suppose that you mean at \(\displaystyle{\mathbb{R}}\)) , we have that : \(\displaystyle{\begin{aligned} F(x)&=\int_{0}^{x}\left((2\,t+3)\,\int_{1}^{2}f(u)\,\mathrm{d}u\right)\,\mathrm{d}t\\&=\int_{1}^{2}f(u)\,\mathrm{d}u\,\...
by Papapetros Vaggelis
Thu Nov 12, 2015 2:20 pm
Forum: Functional Analysis
Topic: Fixed point
Replies: 5
Views: 4544

Fixed point

Let \(\displaystyle{\left(X,||\cdot||\right)}\) be a real \(\displaystyle{\rm{Banach}}\) space and \(\displaystyle{T\in\mathbb{B}(X,X)}\) such that \(\displaystyle{\sum_{n=0}^{\infty}||T^{n}||<\infty}\) . If \(\displaystyle{y\in X}\), then we define \(\displaystyle{S_{y}:X\longrightarrow X}\) by \(\...